3.2746 \(\int \frac {(1-2 x)^{3/2} (2+3 x)^{7/2}}{(3+5 x)^{5/2}} \, dx\)

Optimal. Leaf size=220 \[ -\frac {24369 \sqrt {\frac {3}{11}} \operatorname {EllipticF}\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{109375}-\frac {6 \sqrt {1-2 x} (3 x+2)^{7/2}}{\sqrt {5 x+3}}-\frac {2 (1-2 x)^{3/2} (3 x+2)^{7/2}}{15 (5 x+3)^{3/2}}+\frac {622}{175} \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^{5/2}+\frac {3872 \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^{3/2}}{4375}+\frac {4801 \sqrt {1-2 x} \sqrt {5 x+3} \sqrt {3 x+2}}{21875}-\frac {25643 \sqrt {\frac {11}{3}} E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{109375} \]

[Out]

-2/15*(1-2*x)^(3/2)*(2+3*x)^(7/2)/(3+5*x)^(3/2)-24369/1203125*EllipticF(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(
1/2))*33^(1/2)-25643/328125*EllipticE(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)-6*(2+3*x)^(7/2)*(1-
2*x)^(1/2)/(3+5*x)^(1/2)+3872/4375*(2+3*x)^(3/2)*(1-2*x)^(1/2)*(3+5*x)^(1/2)+622/175*(2+3*x)^(5/2)*(1-2*x)^(1/
2)*(3+5*x)^(1/2)+4801/21875*(1-2*x)^(1/2)*(2+3*x)^(1/2)*(3+5*x)^(1/2)

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Rubi [A]  time = 0.08, antiderivative size = 220, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {97, 150, 154, 158, 113, 119} \[ -\frac {6 \sqrt {1-2 x} (3 x+2)^{7/2}}{\sqrt {5 x+3}}-\frac {2 (1-2 x)^{3/2} (3 x+2)^{7/2}}{15 (5 x+3)^{3/2}}+\frac {622}{175} \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^{5/2}+\frac {3872 \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^{3/2}}{4375}+\frac {4801 \sqrt {1-2 x} \sqrt {5 x+3} \sqrt {3 x+2}}{21875}-\frac {24369 \sqrt {\frac {3}{11}} F\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{109375}-\frac {25643 \sqrt {\frac {11}{3}} E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{109375} \]

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)^(3/2)*(2 + 3*x)^(7/2))/(3 + 5*x)^(5/2),x]

[Out]

(-2*(1 - 2*x)^(3/2)*(2 + 3*x)^(7/2))/(15*(3 + 5*x)^(3/2)) - (6*Sqrt[1 - 2*x]*(2 + 3*x)^(7/2))/Sqrt[3 + 5*x] +
(4801*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*Sqrt[3 + 5*x])/21875 + (3872*Sqrt[1 - 2*x]*(2 + 3*x)^(3/2)*Sqrt[3 + 5*x])/43
75 + (622*Sqrt[1 - 2*x]*(2 + 3*x)^(5/2)*Sqrt[3 + 5*x])/175 - (25643*Sqrt[11/3]*EllipticE[ArcSin[Sqrt[3/7]*Sqrt
[1 - 2*x]], 35/33])/109375 - (24369*Sqrt[3/11]*EllipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/109375

Rule 97

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p)/(b*(m + 1)), x] - Dist[1/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n
- 1)*(e + f*x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && LtQ[m
, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])

Rule 113

Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-((b*e
- a*f)/d), 2]*EllipticE[ArcSin[Sqrt[a + b*x]/Rt[-((b*c - a*d)/d), 2]], (f*(b*c - a*d))/(d*(b*e - a*f))])/b, x
] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] &&  !LtQ[-((b*c - a*d)/d),
0] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[-(d/(b*c - a*d)), 0] && GtQ[d/(d*e - c*f), 0] &&  !LtQ[(b*c - a*d)
/b, 0])

Rule 119

Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-(b/d
), 2]*EllipticF[ArcSin[Sqrt[a + b*x]/(Rt[-(b/d), 2]*Sqrt[(b*c - a*d)/b])], (f*(b*c - a*d))/(d*(b*e - a*f))])/(
b*Sqrt[(b*e - a*f)/b]), x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ[(b*e - a*f)/b, 0] &
& PosQ[-(b/d)] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[(d*e - c*f)/d, 0] && GtQ[-(d/b), 0]) &&  !(SimplerQ[c +
d*x, a + b*x] && GtQ[(-(b*e) + a*f)/f, 0] && GtQ[-(f/b), 0]) &&  !(SimplerQ[e + f*x, a + b*x] && GtQ[(-(d*e)
+ c*f)/f, 0] && GtQ[(-(b*e) + a*f)/f, 0] && (PosQ[-(f/d)] || PosQ[-(f/b)]))

Rule 150

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegersQ[2*m, 2*n, 2*p]

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 158

Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol]
:> Dist[h/f, Int[Sqrt[e + f*x]/(Sqrt[a + b*x]*Sqrt[c + d*x]), x], x] + Dist[(f*g - e*h)/f, Int[1/(Sqrt[a + b*
x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && SimplerQ[a + b*x, e + f*x] &&
SimplerQ[c + d*x, e + f*x]

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{3/2} (2+3 x)^{7/2}}{(3+5 x)^{5/2}} \, dx &=-\frac {2 (1-2 x)^{3/2} (2+3 x)^{7/2}}{15 (3+5 x)^{3/2}}+\frac {2}{15} \int \frac {\left (\frac {9}{2}-30 x\right ) \sqrt {1-2 x} (2+3 x)^{5/2}}{(3+5 x)^{3/2}} \, dx\\ &=-\frac {2 (1-2 x)^{3/2} (2+3 x)^{7/2}}{15 (3+5 x)^{3/2}}-\frac {6 \sqrt {1-2 x} (2+3 x)^{7/2}}{\sqrt {3+5 x}}+\frac {4}{75} \int \frac {\left (\frac {1545}{2}-\frac {4665 x}{2}\right ) (2+3 x)^{5/2}}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=-\frac {2 (1-2 x)^{3/2} (2+3 x)^{7/2}}{15 (3+5 x)^{3/2}}-\frac {6 \sqrt {1-2 x} (2+3 x)^{7/2}}{\sqrt {3+5 x}}+\frac {622}{175} \sqrt {1-2 x} (2+3 x)^{5/2} \sqrt {3+5 x}-\frac {4 \int \frac {(2+3 x)^{3/2} \left (-\frac {15705}{4}+14520 x\right )}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{2625}\\ &=-\frac {2 (1-2 x)^{3/2} (2+3 x)^{7/2}}{15 (3+5 x)^{3/2}}-\frac {6 \sqrt {1-2 x} (2+3 x)^{7/2}}{\sqrt {3+5 x}}+\frac {3872 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{4375}+\frac {622}{175} \sqrt {1-2 x} (2+3 x)^{5/2} \sqrt {3+5 x}+\frac {4 \int \frac {\left (\frac {29625}{2}-\frac {216045 x}{4}\right ) \sqrt {2+3 x}}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{65625}\\ &=-\frac {2 (1-2 x)^{3/2} (2+3 x)^{7/2}}{15 (3+5 x)^{3/2}}-\frac {6 \sqrt {1-2 x} (2+3 x)^{7/2}}{\sqrt {3+5 x}}+\frac {4801 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{21875}+\frac {3872 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{4375}+\frac {622}{175} \sqrt {1-2 x} (2+3 x)^{5/2} \sqrt {3+5 x}-\frac {4 \int \frac {-\frac {2042685}{8}-\frac {1153935 x}{4}}{\sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}} \, dx}{984375}\\ &=-\frac {2 (1-2 x)^{3/2} (2+3 x)^{7/2}}{15 (3+5 x)^{3/2}}-\frac {6 \sqrt {1-2 x} (2+3 x)^{7/2}}{\sqrt {3+5 x}}+\frac {4801 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{21875}+\frac {3872 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{4375}+\frac {622}{175} \sqrt {1-2 x} (2+3 x)^{5/2} \sqrt {3+5 x}+\frac {25643 \int \frac {\sqrt {3+5 x}}{\sqrt {1-2 x} \sqrt {2+3 x}} \, dx}{109375}+\frac {73107 \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}} \, dx}{218750}\\ &=-\frac {2 (1-2 x)^{3/2} (2+3 x)^{7/2}}{15 (3+5 x)^{3/2}}-\frac {6 \sqrt {1-2 x} (2+3 x)^{7/2}}{\sqrt {3+5 x}}+\frac {4801 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{21875}+\frac {3872 \sqrt {1-2 x} (2+3 x)^{3/2} \sqrt {3+5 x}}{4375}+\frac {622}{175} \sqrt {1-2 x} (2+3 x)^{5/2} \sqrt {3+5 x}-\frac {25643 \sqrt {\frac {11}{3}} E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{109375}-\frac {24369 \sqrt {\frac {3}{11}} F\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{109375}\\ \end {align*}

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Mathematica [A]  time = 0.41, size = 112, normalized size = 0.51 \[ \frac {168035 \sqrt {2} \operatorname {EllipticF}\left (\sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right ),-\frac {33}{2}\right )+\frac {10 \sqrt {1-2 x} \sqrt {3 x+2} \left (-202500 x^4-189000 x^3+174525 x^2+216050 x+52067\right )}{(5 x+3)^{3/2}}+51286 \sqrt {2} E\left (\sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )|-\frac {33}{2}\right )}{656250} \]

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)^(3/2)*(2 + 3*x)^(7/2))/(3 + 5*x)^(5/2),x]

[Out]

((10*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*(52067 + 216050*x + 174525*x^2 - 189000*x^3 - 202500*x^4))/(3 + 5*x)^(3/2) +
51286*Sqrt[2]*EllipticE[ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2] + 168035*Sqrt[2]*EllipticF[ArcSin[Sqrt[2/11]*
Sqrt[3 + 5*x]], -33/2])/656250

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fricas [F]  time = 0.65, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {{\left (54 \, x^{4} + 81 \, x^{3} + 18 \, x^{2} - 20 \, x - 8\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1}}{125 \, x^{3} + 225 \, x^{2} + 135 \, x + 27}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(2+3*x)^(7/2)/(3+5*x)^(5/2),x, algorithm="fricas")

[Out]

integral(-(54*x^4 + 81*x^3 + 18*x^2 - 20*x - 8)*sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1)/(125*x^3 + 225*x^2
+ 135*x + 27), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{\frac {7}{2}} {\left (-2 \, x + 1\right )}^{\frac {3}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(2+3*x)^(7/2)/(3+5*x)^(5/2),x, algorithm="giac")

[Out]

integrate((3*x + 2)^(7/2)*(-2*x + 1)^(3/2)/(5*x + 3)^(5/2), x)

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maple [C]  time = 0.02, size = 234, normalized size = 1.06 \[ -\frac {\left (12150000 x^{6}[phone] x^{5}-12631500 x^{4}-18488250 x^{3}-1794020 x^{2}+256430 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, x \EllipticE \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )+840175 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, x \EllipticF \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )+3800330 x +153858 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, \EllipticE \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )+504105 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, \EllipticF \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )+1041340\right ) \sqrt {3 x +2}\, \sqrt {-2 x +1}}{656250 \left (6 x^{2}+x -2\right ) \left (5 x +3\right )^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(3/2)*(3*x+2)^(7/2)/(5*x+3)^(5/2),x)

[Out]

-1/656250*(840175*2^(1/2)*EllipticF(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2))*x*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+
1)^(1/2)+256430*2^(1/2)*EllipticE(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2))*x*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+1)
^(1/2)[phone]*x^6+504105*2^(1/2)*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+1)^(1/2)*EllipticF(1/11*(110*x+66)^(1/2),
1/2*I*66^(1/2))+153858*2^(1/2)*(5*x+3)^(1/2)*(3*x+2)^(1/2)*(-2*x+1)^(1/2)*EllipticE(1/11*(110*x+66)^(1/2),1/2*
I*66^(1/2))[phone]*x^5-12631500*x^4-18488250*x^3-1794020*x^2+3800330*x+1041340)*(3*x+2)^(1/2)*(-2*x+1)^(1/2)
/(6*x^2+x-2)/(5*x+3)^(3/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{\frac {7}{2}} {\left (-2 \, x + 1\right )}^{\frac {3}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)*(2+3*x)^(7/2)/(3+5*x)^(5/2),x, algorithm="maxima")

[Out]

integrate((3*x + 2)^(7/2)*(-2*x + 1)^(3/2)/(5*x + 3)^(5/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (1-2\,x\right )}^{3/2}\,{\left (3\,x+2\right )}^{7/2}}{{\left (5\,x+3\right )}^{5/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((1 - 2*x)^(3/2)*(3*x + 2)^(7/2))/(5*x + 3)^(5/2),x)

[Out]

int(((1 - 2*x)^(3/2)*(3*x + 2)^(7/2))/(5*x + 3)^(5/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(3/2)*(2+3*x)**(7/2)/(3+5*x)**(5/2),x)

[Out]

Timed out

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